Question

the ratio of the sides of a parallelogram is 3: 5 and the perimeter is 48cm find the sides

Answer 1

Answer:

Let the sides be 3x and 5x respectively,

Since, perimeter of parallelogram = 2 ( l+b)

ATQ,

2 ( 3x + 5x) = 48

2 ( 8x) = 48

8x = 24

x = 24/8

x = 3

So, The sides are, 3x = 9cm and 5x = 15cm

Hope This helps ☺️

Answer 2

Given :-

• The ratio of the sides of a parallelogram is 3: 5 and the perimeter is 48cm

To Find :-

• What are the sides of it ?

Formula Used :-

$\bigstar \: \boxed{ \bf Perimeter_{(Parallelogram)} \: = \: 2(l+b)} \: \bigstar$

Solution :-

Given that,

$⇝\;$ The perimeter of a parallelogram is 48cm

$⇝\;$The ratio of the sides of a parallelogram is 3 : 5

Let,

$⟶\;$ 3 : 5 = 3x and 5x

According to the question by using formula we get,

$\sf \implies \: Perimeter \: = \: 2(l+b)$

$\sf \implies \: 48 \: = \: 2(3x+5x)$

$\sf \implies \: 48 \: = \: 2(8x)$

$\sf \implies \: 48 \: = \: 16x$

$\displaystyle\sf \implies \: \frac{3}{1} \: = \: x$

$\displaystyle\sf \implies \: 3 \: = \: x$

$\displaystyle\bf \implies \: \underline{x \: = \: 3}$

Hence,

The sides of a parallelogram :

$\longmapsto \: \: \sf3x = 3(3) = \bf 9cm$

$\longmapsto \: \: \sf5x = 5(3) = \bf 15cm$

Finally,

$\boxed{ \bf \therefore The \: sides \: of \: a \: parallelogram \: are \: 9cm \: and \: 15cm}$