the ratio of the sides of an isosceles triangle is 4:4:3. If the perimeter is 66 cm, find the base and the area
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4x+4x+3x=66
11x=66
x=66/11
x=6
then, 4x=4*6=24, 4x=4*6=24, 3x=3*6=18
a=24,b=24,c=18
s=a+b+c/2
s=24+24+18/2
s=66
area of triangle= √66(66-24)(66-24)(66-18)
=√66*42*42*48
=42√66*48
=42√2*3*11*2*2*2*2*3
=42*2*2*3√11*2
=504√22 Answer
area= 504√ 22
base = 18
11x=66
x=66/11
x=6
then, 4x=4*6=24, 4x=4*6=24, 3x=3*6=18
a=24,b=24,c=18
s=a+b+c/2
s=24+24+18/2
s=66
area of triangle= √66(66-24)(66-24)(66-18)
=√66*42*42*48
=42√66*48
=42√2*3*11*2*2*2*2*3
=42*2*2*3√11*2
=504√22 Answer
area= 504√ 22
base = 18
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