The ratio of the speed of two trains A and B running in the opposite direction is 5:15. If each
train is 200 m long and crosses each other in 10 s, then find the amount of time (in seconds)
that train A takes to cross a man standing on a platform.
Answers
Answer:
20 is the answer
Step-by-step explanation:
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Given : The ratio of the speed of two trains A and B running in the opposite direction is 5:15. each train is 200 m long and crosses each other in 10 s
To Find : the amount of time (in seconds) that train A takes to cross a man standing on a platform.
Solution:
Speed of Train A = 5S m/s
Speed of Train B = 15S m/s
Running in opposite direction :
Relative speed = 5S + 15S = 20S m/s
Each train 200 m long
Total distance = 200 + 200 = 400m
Time = 10 sec
Speed = 400/10 = 40 m/s
20S = 40
=> S = 2
Speed of Train A = 10 m/s
Speed of Train B = 30 m/s
find the amount of time (in seconds) that train A takes to cross a man standing on a platform. = 200/10 = 20 secs
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