Math, asked by AyushRoutray, 8 months ago

The ratio of the speed of two trains A and B running in the opposite direction is 5:15. If each
train is 200 m long and crosses each other in 10 s, then find the amount of time (in seconds)
that train A takes to cross a man standing on a platform.​

Answers

Answered by saidhanushkasi89
11

Answer:

20 is the answer

Step-by-step explanation:

please send me thanks and like me ❤️ plz ❤️❤️ plz............

Answered by amitnrw
0

Given  : The ratio of the speed of two trains A and B running in the opposite direction is 5:15.  each  train is 200 m long and crosses each other in 10 s

To Find : the amount of time (in seconds)  that train A takes to cross a man standing on a platform.​

Solution:

Speed of Train  A   = 5S  m/s

Speed of Train  B =  15S  m/s

Running in opposite direction :

Relative speed = 5S + 15S = 20S  m/s

Each train 200 m long

Total distance = 200 + 200 = 400m

Time = 10 sec

Speed = 400/10  = 40 m/s

20S  = 40

=> S = 2

Speed of Train  A   = 10 m/s

Speed of Train  B =  30  m/s

find the amount of time (in seconds)  that train A takes to cross a man standing on a platform.​   =  200/10  = 20 secs

Learn More:

speed of car is 2/3 rd of speed of train if train covered 1100 metres in ...

https://brainly.in/question/13000975

An express train takes 1 hour less than a passenger train to travel ...

https://brainly.in/question/15927656

Similar questions