Question

the ratio of the speeds of two trains is 6:5.The second train runs 700 km in 4 hours and the first train runs 1260 km in h hours. The remainder obtained on the division of h^2 by 10 is

Answer 1

Answer:

Time taken by the first train will be 6 hours.

Step-by-step explanation:

Ratio = 6:5

Second train distance = 700 km

Time = 4 hrs

Second train speed = Distance/Time

= 700/4 km/hr

= 175 km/hr

First train distance = 1260 km

Time = h hrs

From the ratio,

175 km/hr is the 5 so,

= (175/5) km/hr

= 35 km/hr

Speed of first train = (35*6) km/hr

= 210 km/hr

So, the time taken by first train is = S = D/T

= 210 = 1260/T

= 210T = 2160

= T = 6 hrs

Hope this helps.

Answer 2

Answer:

The speed of first train is equal to 210km/hr and time taken by the first train to cover the distance of 1260km is 6hours.

Step-by-step explanation:

Given: Distance covered by first train  $D_{1}=1260km$

Distance covered by second train, $D_{2}=700km$

Time taken by second train $T_{2}=4hr$

Speed of second train, $S_{2}=\frac{D_{2}}{T_{2}}= \frac{700}{4}=175Km/hr$

Now, given the ratio of speeds of two train is $6:5$,

Consider it as $6x:5x$

From the speed of second train, we can say;

   $5x=175km/hr$

⇒  $x=\frac{175}{5}$

⇒  $x=35Kmhr^{-1}$

Therefore the speed of first train, $S_{1}=6*35=210km/hr$

The time taken by 1st train, $T_{1}=\frac{D_{1}}{S_{1}}$

                                           $T_{1}=\frac{1260}{210}\\ T_{1}=6hours$