Math, asked by kinjalknsingh, 8 months ago

the ratio of the sum and poduct of roots of the equation 7x square -12x +18 =0 is ? a)7:12 b)7:18 c)3:2 d)2:3

Answers

Answered by Mysterioushine
16

GIVEN : -

  • Quadratic equation is 7x - 12x + 18 = 0

TO FIND : -

  • Ratio of Sum of roots and Product of roots

SOLUTION :-

The general form of a quadratic equation is ax² + bx + c = 0 and let us assume that these roots are h , k

Then relation between h , k , a , b , c is given by

\large\tt{(h+k)\:=\:\frac{-b}{a}}

\large\tt{(hk)\:=\:\frac{c}{a}}

Given equation is 7x²-12x + 18 = 0

Let the roots of the given equation be λ , β

By comparing we get ,

  • a = 7
  • b = -12
  • c = 18

\large\tt{\rightarrow{(\lambda+\beta)\:=\:\frac{-(-12)}{7}\:=\:\frac{12}{7}}}

\large\tt{\rightarrow{(\lambda.\beta)\:=\:\frac{18}{7}}}

We got the sum of the roots as 12/7 and product of roots is 18/7 .

\large\tt{Ratio\:=\:\frac{12}{7}\::\:\frac{18}{7}}

\large\tt{\rightarrow{Ratio\:=\:12:18\:=\:2:3}}

∴ The Ratio between the Sum of roots and product of roots of given quadratic equation is 2:3

Hence , Option(d) is correct

\large\tt{\underline{\underline{\green{Additional\:Information:-}}}}

❃ If in a quadratic equation ax² + bx + c = 0 , Discriminant i.e, b² - 4ac = 0 then roots of this equation are real and equal

  • If b² - 4ac > 0 , Roots are real and distinct
  • If b² - 4ac < 0 , Roots are not real
Answered by MisterIncredible
18

Question : -

The ratio of the sum and product of the roots of the quadratic equation 7x² - 12x + 18 = 0 is ?

  • a ) 7 : 12

  • b ) 7 : 18

  • c ) 3 : 2

  • d ) 2 : 3

Answer : -

Given : -

Quadratic equation : 7x² - 12x + 18 = 0

Required to find : -

  • Ratio of the sum and product of the roots ?

Conditions used : -

Here, conditions refer to the relationship between the zeroes and the coefficients of the quadratic equation .

\boxed{\tt{ \alpha + \beta = \dfrac{- coefficient \ of \ x^2 }{Coefficient \ of \ x }}}

\boxed{\tt{ \alpha \beta = \dfrac{ constant \ term }{ Coefficient \ of \ x^2 } }}

Solution : -

Quadratic equation : 7x² - 12x + 18 = 0

We need to find the ratio of the sum and product of the roots ?

So,

Let find the roots of the equation .

The standard form of the Quadratic equation is ax² + bx + c = 0

Now,

Let's compare this standard form of the Quadratic equation with the given polynomial .

Hence,

  • a = 7

  • b = - 12

  • c = 18

Let's find the value of the sum of the roots and the product of the roots .

Here,

Let's consider that alpha ( α ) , beta ( β ) are the roots of the quadratic equation .

We know that ;

The relationship between the sum of the zeroes and the coefficients is ;

\boxed{\tt{ \alpha + \beta = \dfrac{- coefficient \ of \ x^2 }{Coefficient \ of \ x }}}

So,

This implies ;

➪ α + β = - b/a

➪ α + β = - ( - 12 )/7

➪ α + β = 12/7

Hence,

  • Value of sum of the roots = 12/7

Similarly,

The relationship between the product of the zeroes and the coefficients is ;

\boxed{\tt{ \alpha \beta = \dfrac{ constant \ term }{ Coefficient \ of \ x^2 } }}

This implies ;

➪ α.β = c/a

➪ α.β = 18/7

Hence,

  • Value of product of the roots = 18/7

Now,

Let's find the ratio of the sum of the roots is to product of the roots

This implies ;

➪ α + β : α.β

➪ 12/7 : 18/7

However,

we know that ;

a : b can also be written as a/b

So,

➪ α + β : α.β

➪ 12/7 ÷ 18/7

➪ 12/7 x 7/18

➪ 12/18

➪ 12 : 18

By reducing using 6 table we get ;

2 : 3

Therefore,

The ratio of the sum and the product of the roots is 2 : 3

Hence,

Option - d is correct

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