The ratio of the volumes of 11 g of CO2 and 28 g of CO at STP
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Answer:
the ratio = 5.6:22.4 = 1:4
Explanation:
Volume of 44g of CO 2 at STP = 22.4L
Volume of 11g of CO 2 at STP = 22.4/44 ×11 = 5.6L
Also volume of 28g of CO at STP = 22.4L
Therefore
the ratio = 5.6:22.4 = 1:4
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