The ratio of the volumes of the two cones is 4: 5 and the ratio of the radii of their bases is 2: 3.
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Let the radius be r1: r2 =2x: 3x
V1: V2= 4x:5x
Height be h1 & h2
[ Vol . Of cone=( ⅓)π r²h]
1/3π r1²h1: 1/3πr2²h2= 4x:5x
r1²h1:r2²h2=4x:5x
r1²h1/ r2²h2=4x:5x
[ r1: r2=2x:3x]
( 2x²)h1/(3x²)h2 =4x:5x
4h1/9h2=4:5
V1/V2
4h1/9h2= 4/5
h1/h2= (⅘) × 9/4
h1/h2= 9/5
h1:h2= 9/5
Hence, the ratio of heights of the two cones are(h1:h2)= 9:5
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V1: V2= 4x:5x
Height be h1 & h2
[ Vol . Of cone=( ⅓)π r²h]
1/3π r1²h1: 1/3πr2²h2= 4x:5x
r1²h1:r2²h2=4x:5x
r1²h1/ r2²h2=4x:5x
[ r1: r2=2x:3x]
( 2x²)h1/(3x²)h2 =4x:5x
4h1/9h2=4:5
V1/V2
4h1/9h2= 4/5
h1/h2= (⅘) × 9/4
h1/h2= 9/5
h1:h2= 9/5
Hence, the ratio of heights of the two cones are(h1:h2)= 9:5
HEY MATE PLEASE MARK ME AS A BRAINLIST ANSWER
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