Math, asked by soniasinghal731, 1 year ago

The ratio of the volumes of three buckets is 3:4:5. Buckets contain the mixture of water and alcohol. If the mixture contains water and alcohol in the ratio 1:4 , 1:3, 2:5 respectively, then find the ratio of water and alcohol when the mixture in all containers is poured into a fourth container.

Answers

Answered by maddy0507
2

 \frac{3}{4} \times  \frac{3x + 4x}{3}  +  \frac{3}{5}  \times 5x
y =  \frac{79}{144}
alcohol to water
Answered by hardikanonymous
7

Answer:

The answer is 157:53.

Step-by-step explanation:

Let the volumes be 3x,4x,5x respectively.

Container with volume 3x:  

Alcohol = (4/4+1)*3x

Water = (1/4+1)*3x

Container with volume 4x:

Alcohol = (3/1+3)*4x            

Water = (1/3+1)*4x

Container with volume 5x:

Alcohol = (5/2+5)*5x

Water = (2/5+2)*5x

Total Alcohol = 12x/5 + 12x/4 + 25x/7 = 1256x/140

Total Water = 3x/5+ 4x/4 + 10x/7 = 424x/140

Therefore, the ratio of milk to water in 4th container = 1256/424 = 157:53

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