The ratio of the weight of 1.0 L of a gas to the weight of 1.0 L oxygen gas both measured atN.T.P is 2.22. The molecular weight of the gas is:
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NTP: P=1 * 10⁵ Pa T = 298 ⁰K V = 1.0 L
M1 = molecular mass of Oxygen = 32
P V = n R T = (W/M) R T Ideal gas equation.
Since, P, V and T are same for both unknown gas and oxygen,
n= W1/M1 = W2/M2
M2/M1 = W2/W1
M2 = 2.22 * 32 = 71.04
M1 = molecular mass of Oxygen = 32
P V = n R T = (W/M) R T Ideal gas equation.
Since, P, V and T are same for both unknown gas and oxygen,
n= W1/M1 = W2/M2
M2/M1 = W2/W1
M2 = 2.22 * 32 = 71.04
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