Question

the ratio of the weight of a man in a stationary lift and when it is moving downwards with the uniform acceleration 'a' is 3:2. The value of 'a' is ..???

Answer 1

Explanation:

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Answer 2

Given that,

Ratio of weight and acceleration = 3:2

According to question,

When the lift is stationary then the weight of the man

$W'=mg$

When it is moving downwards with the uniform acceleration then the weight of the man

$W=mg-ma$

We need to calculate the value of a

Using given data

$\dfrac{W'}{W}=\dfrac{mg}{mg-ma}$

Put the value into the formula

$\dfrac{3}{2}=\dfrac{g}{g-a}$

$3g-3a=2g$

$3g-2g=3a$

$g=3a$

$a=\dfrac{g}{3}$

Hence, The value of a is $\dfrac{g}{3}$