The ratio of the weight of a man in a stationary lift and in a lift accelerating downwards with the a uniform acceleration 'a' is 3:2. The acceleration of the lift is
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Answer:
10/3 m/s^2
Explanation:
mg/mg-ma =3/2
g/g-a=3/2
10/10-a=3/2
3a=10
a =10/3
hope it will help you.....
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