The ratio of the weight of the man in a stationary lift and when it is moving downward with uniform acceleration 'a' 3:2. The value of a 'a' is : (g = acceleration due to gravity)
a) 3/2 g b) g c) 2/3 g d) g/3
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Answered by
0
Answer:
Explanation:
When the lift is stationary, the weight of the man is W
0
=mg
The weight of the man when the lift is moving downward with acceleration a is W=mg-ma
Given,
W
W
0
=
2
3
⇒
mg−ma
mg
=
2
3
⇒2g=3g−3a
∴a=
3
g
Answered by
0
Answer:d. g/3
Explanation:
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