The ratio of three angle of a quadrilateral is 8:6:5.If the fourth angle is 132 degrees,what is the third largest angle ?
Answers
Answered by
1
Let's assume the three angles of the Quadrilateral as
8x , 6x & 5x
We know,
Sum of all angles of Quadrilateral
= 360°
According to Question,
8x + 6x + 5x + 132 = 360
=> 19x = 360 - 132
=> 19x = 228
=> x = 228 / 19
=> x = 12
Required Angles -
1... 8x = 8(12) = 96°
2...6x = 6(12) = 72°
3...5x = 5(12) = 60°
4... 132°
∵ Clearly,
132° > 96° > 72° > 60°
Hence, the third Largest Angle is 72°
8x , 6x & 5x
We know,
Sum of all angles of Quadrilateral
= 360°
According to Question,
8x + 6x + 5x + 132 = 360
=> 19x = 360 - 132
=> 19x = 228
=> x = 228 / 19
=> x = 12
Required Angles -
1... 8x = 8(12) = 96°
2...6x = 6(12) = 72°
3...5x = 5(12) = 60°
4... 132°
∵ Clearly,
132° > 96° > 72° > 60°
Hence, the third Largest Angle is 72°
Answered by
0
Ratio=8:6:5
Let,
1st angle=8x
2nd angle =6x
3rd angle =5x
In a quadrilateral, sum of all angles is 360°
So,
8x+6x+5x+132=360
19x=228
x=12
1st angle =8×12=96
2nd angle =6×12=72
3rd angle =5×12=60
4th angle=132
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