Question

The ratio of time period of electron in first and second orbit of hydrogen atom would be

Answer 1

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Answer 2

Answer:

Ratio will be : 1 : 8

Explanation:

The time of revolution in nth orbit is given by the following relation :

$T_n=\dfrac{4\epsilon_0^2h^3}{me^4}\dfrac{n^3}{Z^2}$

It is clear that time period is directly proportional to the number of orbit.

Let T₁ and T₂ are the time period of the first and the second orbit  of hydrogen orbit.

$\dfrac{T_1}{T_2}=(\dfrac{n_1}{n_2})^3$

$\dfrac{T_1}{T_2}=(\dfrac{1}{2})^3$

$\dfrac{T_1}{T_2}=(\dfrac{1}{8})$

The ratio of time period of first and second orbit is 1 : 8.