Question

The ratio of time periods in first and third orbits of hydrogen atom is :-
(1) 1:3
(2) 1:4
(3) 1:27
(4)1:9​

Answer 1

Answer:

1:9 is the correct one

Explanation:

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Answer 2

Answer:

ratio of T1/T3 = 1/27 Or 1:27

Explanation:

we know that,

the time period of an electron is given by,

T = $\frac{n^3h^3}{4\pi ^2mZ^2e^4}$

( Where, n= orbital no. z = atomic no.  e = charge of the electron , m = mass of the electron, h = Bohr hydrogen atom).

for first orbit. where n=1

T1 = $\frac{n^3h^3}{4\pi ^2mZ^2e^4}$

For third orbit, where n = 3

T3 = 27 $\frac{h^3}{4\pi ^2mZ^2e^2}$

therefore, ratio of T1/T3 = 1/27 Or 1:27

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