Question

The ratio of time periods of two simple pendulums of length 1 m and 16 m at a place is 1: 4.
plz i need it very fast

Answer 1

Answer:

4

Explanation:

lets say they are again in phase when shorter pendulum has made n

1

oscillations and bigger pendulum n

2

oscillations. so total time elapsed =T

1

×n

1

=T

2

×n

2

⇒

n

2

n

1

=

T

1

T

2

=

l

1

l

2

=

1

16

=

1

4

they will again be in phase for the first time when the shorter pendulum has made 4 oscillations and the longer pendulum has made 1 oscillation.