The ratio of tin and zinc in an alloy is 3:4.In 21 gm of alloy,find the quantity of tin and zinc
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Quantity ofTin and Alloy in an alloy of 21g is as follows:
Tin:9g
Zinc:12g
Hope it helps
Tin:9g
Zinc:12g
Hope it helps
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Answered by
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The quantity of tin=3/4+3*21gm=3/7*21=9 gm
The quantity of zinc = 4/4+3*21gm= 4/7*21 Gm =12 Gm
We can solve this by this formula =share of a/share of a + share of b* given quantity
The quantity of zinc = 4/4+3*21gm= 4/7*21 Gm =12 Gm
We can solve this by this formula =share of a/share of a + share of b* given quantity
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