The ratio of tin and zinc in an alloy is 3:4, In 21 gm of alloy, find the quantity of (i) tin and (ii) zinc
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Step-by-step explanation:
There are two methods to solve this problem:-
1) Algebric Method
let quantity of tin and zinc be 3x and 4x respectively
Total quantity of allow is 21g
3x+4x = 21
7x = 21
x = 21/7
x = 3
tin = 3×3 = 9g
zinc = 3×4 = 12g
2) Ratio method
Ratio of tin and zinc is 3:4
Total parts = 7
Total quantity of alloy = 21g
Tin = 3/7×21 = 9g
Zinc = 4/7×21 = 12g
You may choose the one which you understand more clearly.
Hope it helps
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