Chemistry, asked by SiddhartGupta, 1 month ago

the ratio of total volume of bcc to simple cubic structure is​

Answers

Answered by ambarshabir90373
7

Answer:

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Answered by anvitanvar032
0

Answer:

The correct answer of this question is \frac{8}{3\sqrt{3} }

Explanation:

Given - The ratio of total volume of bcc to simple cubic structure.

To Find - Write the ratio of total volume of bcc to simple cubic structure is​The volume of the atoms in the unit cell divided by the volume of the unit cell is the APF of a BCC structure. As a result, a BCC unit cell's packing factor is always 0.68. A face-centered cubic unit cell, on the other hand, has a packing factor of 0.74.

The simple cubic is r = \frac{a}{c} or  a  = 2r

The volume of simple cubic unit cell is (2^{3} ) = 8r^{3}

Volume of bcc unit cell / Volume of simple cubic = \frac{64r^{3}/3\sqrt{3}  }{8r^{3} }

\frac{64}{8 . 3\sqrt{3} } = \frac{8}{3\sqrt{3} }

#SPJ2

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