Question

The ratio of turns in the primary and secondary coil of a transformer is 1:15. If the voltage and current in the primary coil are 12 volt and 30 ampere respectively, then what will be the voltage and current in secondary coil?
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Answer 1

Answer:

The ratio of turns in the primary and secondary coil of a transformer is 1:15. If the voltage and current in the primary coil are 12 volts and 30 amperes respectively, then the voltage and current in the secondary coil is 180v and 2A respectively

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

the ratio of turns $N_{1} /N_{2} =1/15$

the voltage in the primary coil is $V_{1} =12v$

therefore voltage in the secondary coil is $V_{2} =\frac{V_{1} N_{2} }{N_{1} }$

⇒$V_{2} =12*15/1=180v$

current in the primary coil $I_{1} =30A$

current in the secondary coil is ${I_{2} }={I_{1} }\frac{N_{1} }{N_{2} }$

⇒$I_{2} =30*1/15=2A$

Answer 2

Answer:

30 amperes respectively, then the voltage and current in the secondary coil is 180v

Explanation:

correct answer