the ratio of two adjacent side of a parallelogram
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Let ABCD the parallelogram
Let , AD=BC=2x. (opposite sides are equal)
AB=DC=3x. (opposite side are equal)
Perimeter=40
2×{l+b}=40
2×{2x+3x}=40
x=4cm
Since, AD=BC=2×4=8cm. Ans
AB=DC=3×4=12cm. Ans
Let , AD=BC=2x. (opposite sides are equal)
AB=DC=3x. (opposite side are equal)
Perimeter=40
2×{l+b}=40
2×{2x+3x}=40
x=4cm
Since, AD=BC=2×4=8cm. Ans
AB=DC=3×4=12cm. Ans
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0
ANSWER
AB = 8 cm
AB = 8 cmBC = 12 cm
AB = 8 cmBC = 12 cmCD = 8 cm
AB = 8 cmBC = 12 cmCD = 8 cmDA = 12 cm
STEP BY STEP EXPLANATION
let ABCD be a parallelogram
ATQ,
AB : BC = 2:3
let the ratio be x
then adjescent sides will be 2x and 3x
AB = CD = 2x and BC = AD = 3x [opposite sides]
given perimeter = 40 cm
ATQ,
2x + 3x + 2x + 3x = 40
10x = 40
now ,
sides = 2x = 2(4) = 8 cm
3x = 3(4) = 12 cm
SO,
AB = 8 cm
BC = 12 cm
CD = 8 cm
DA = 12 cm
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