Question

the ratio of two different adjacent sides of a parallelogram is 2 ratio 3 its perimeter is 50 cm find the area if altitude corresponding to largest side is 10 cm

Answer 1

Hey there !!


→ Given :-

→ A parallelogram, in which adjacent sides are in ratio 2:3.

→ Perimeter of parallelogram = 50cm.

→ Altitude corresponding to largest side = 10cm.


▶Now,

→ Let the ratio be x.

→ Length = 3x.

→ Breadth = 2x.


▶ Perimeter of parallelogram = 2( Length + breadth ).

=> 50 = 2( 3x + 2x ).

=> 50 = 2 × 5x.

=> 50 = 10x.

=> x = $\frac{50}{10}$ .

=> x = 5.


➡ Then, length = 3x = 3 × 5 = 15cm.

And, breadth = 2x = 2 × 5 = 10cm.


↪ Length is the largest side of parallelogram.

=> Area of parallelogram = base × height.

= 15 × 10.

$\huge \boxex{ = 150{cm}^{2}.}$


✔✔ Hence, it is solved ✅✅.

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$\huge \boxed{ \mathbb{THANKS}}$



$\huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}$

Answer 2

$\huge{hey}$

$\huge \bf{here \: is \: answer}$

let the ratio of the sides be x

hence

2x and 3x

perimeter of parallelogram =2(l+b)

2(2x+3x)=50

2(5x)=50

10x=50

$\sf{x = \frac{50}{10}}$

hence

$\bf{x = 5 \: cm}$

hence

side of parallelogram

2x=2×5=10cm

3x=3×5=15 cm

hence

longest side is 15 cm

area = base ×height

hence

10 ×15

$\huge\bf{150cm2}$
$\huge{ \mathfrak{hope \: it \: helps}}$

$\huge{ \mathbb{THANKS}}$