the ratio of two number 4:5 and the difference of the cube of the number is 1647. Find the sum of the number
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Let numbers are 4x and 5x
Given, Difference of their cube = 1647
hence, ( 5x )^3 - ( 4x )^3 = 1647
=> 125x^3 - 64x^3 = 1647
=> 61 x^3 = 1647
=> x^3 = 1647 / 61
=> x^3 = 27
=> x^3 = 3^3
Due to this, x = 3
Numbers are 4x = 4( 3 ) = 12
And, 5x = 5( 3 ) = 15
Their sum = 12 + 15
=> 27
Given, Difference of their cube = 1647
hence, ( 5x )^3 - ( 4x )^3 = 1647
=> 125x^3 - 64x^3 = 1647
=> 61 x^3 = 1647
=> x^3 = 1647 / 61
=> x^3 = 27
=> x^3 = 3^3
Due to this, x = 3
Numbers are 4x = 4( 3 ) = 12
And, 5x = 5( 3 ) = 15
Their sum = 12 + 15
=> 27
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hope this helps you....
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