Question

the ratio of two numbers is 7:8.if first number is increased by 20% and second number is increased by 10% what will be the new ratio?​

Answer 1

Explanation -:

Given :

• Ratio of two numbers = 7 : 8
• First number is increased by 20%
• Second number is increased by 10%

To Find :

• New ratio

Solution :

Let us assume the number as '7x' and '8x'

According To Question

First number is increased by 20%

$\small\rm{Total \: increased \: in \: first \: number = 120\% \: of \: 7x}$

$⇢ \small\rm{ \dfrac{120}{100} \times 7x }$

$⇢ \small\rm{ \dfrac{6}{5} \times 7x}$

$⇢ \small\rm{ \dfrac{42x}{5} }$

Second number is increased by 10%

$\small\rm{ Total \: increased \: in \: second \: number = 110\% \: of \: 8x}$

$⇢ \small\rm{ \dfrac{110}{100} \times 8x}$

$⇢ \small\rm{ \dfrac{11}{5} \times 4x }$

$⇢\small\rm{ \dfrac{44x}{5} }$

$\small\rm {Required \: ratio = \dfrac{ \cancel{42x}}{ \cancel{5}} \ratio \dfrac{ \cancel{44x}}{ \cancel{5}} = 21 \ratio22 }$