Question

the ratio of two quantities is 7:11, and their difference is 44. Find the sum of the two quantities.​

Answer 1

Answer:

let the common factor= x

ratio = 7:11

1st number = 7x

2nd number = 11x

difference = 44

ATQ,

7x-11x= 44

= -4x = 44

= x = 44/-4

= x = -11

therefore,

1st number= 7×-11=-77

2nd number= 11×-11= -121

there sum = -77+(-121)

= -77-121

= -198ans.

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Answer 2

here,

let the ratio 7:11 be 7x and 11x respectively,

then,

according to question,

7x-11x=44

or,4x=44

or,x=44/4

∴ x=11

so,

7x=7×11  =77

11x=11×11=121

now,

121+77

=198 ans