Question

the ratio of two supplementary angles is 3:2. Find the angles. ​

Answer 1

let one angle=3x

another angle=2x

3x+2x=180

5x=180

X=180/5

X=36

then one angle=3x

=3(36)

=108

second angle=2x

=2(36)

=72

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Answer 2

→ Hey Mate,

→ Given Question:-

→ Two supplementary angles are in the ratio 2 : 3. Find the angles.

→ To Find :-

→ The Angles?

→ Solution:-

→ Let the two angles be 2x and 3x in degrees .

→ ∴ 2x + 3x = 180 ,

→ 5x = 180 ⇒ x = 36

→ Thus , the measure of two angles are 2x  = 2 × 36°

→ = 72° and 3x = 3 × 36° = 108 °.

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