Question

the ratio of value of magnetic field at same distance from mid point of a small magnet at its axial and equatorial position is

Answer 1

magnetic induction at the point on the equator of a magnet is given by,
$B=\frac{\mu_0}{4\pi}\frac{M}{r^3}$

where $\mu_0$ is permeability of medium, M is magnetic moment and r is the distance between midpoint of magnet and poijt of observation.

again, magnetic induction of a point on the axis of a magnet is given by,
$B'=\frac{\mu_0}{4\pi}\frac{2M}{r^3}$

now, ratio of magnetic field = B'/B

= $\frac{\mu_0}{4\pi}\frac{2M}{r^3}$/$\frac{\mu_0}{4\pi}\frac{M}{r^3}$

= 2/1