Question

The ratio of volume occupied by 1 mole water vapour at NTP & 1 MOL liquid water is:






With solution
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Answer 1

Answer:

At 1 NTP, 1 mole of a gas is equal to 22.4 L. Hence, 33.6 L of water vapour corresponds to 22.

Explanation:

Answer 2

the ratio of volume occupied by one mole of water vapour at normal temperature pressure and one mole of liquid water is 1.24

Explanation:

• One mole of liquid water is equal to to 18 grams of water. According to the density of water at normal temperature pressure the value 1gram per centimetre cube.
• hence the volume which is occupied by 18 grams of water will be equal to 18 cm ³ or 18 ml.
• The volume which is occupied by 1 mole of water vapour is equal to 22.4 ml

Hence the ratio of the two will be $\frac{22.4}{18}$ = 1.24

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