Question

the ratio of water and acid is 45l solution of acid and water is 5:4 in this sol 15l of water is added. Now in 144 ml of the resulting solution 52ml acid is mixed what is the ratio of the water and acid in final solution​

Answer 1

Answer:

Let's add x litres of water

Now if the solution is 45% acid then it is 55% water.

Equating water in initial and final solution, When solution is 25% acid:

x+0.55(1125)=0.75(x+1125)

x+618.75=0.75x+843.75

0.25x=225

x=900 (to get 25% of acidic solution)

Equating water in initial and final solution, When solution is 30% acid:

x+0.55(1125)=0.7(x+1125)

x+618.75=0.7x+787.5

0.3x=168.75

x=562.5 (to get 30% of acidic solution)

i.e 562.5<x<900