Question

The ratio of wave number of the last line of Paschen ` series and the last line of Lyman series is `​

Answer 1

Answer:

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Explanation:

wave number=2pi/lamda

lamda-p/lamda-L=1:9

Answer 2

Wave-number for last line in Lyman series:

$\overline{ \gamma } = R \bigg \{\dfrac{1}{ {( n_{1}) }^{2} } - \dfrac{1}{ {( n_{2})}^{2} } \bigg \}$

$\implies \overline{ \gamma } = R \bigg \{\dfrac{1}{ {(1) }^{2} } - \dfrac{1}{ {( \infty)}^{2} } \bigg \}$

$\implies \overline{ \gamma } = R \bigg \{1 - 0\bigg \}$

$\implies \overline{ \gamma } = R$

Wave-number for last line in Paschen Series:

$\overline{ \gamma } = R \bigg \{\dfrac{1}{ {( n_{1}) }^{2} } - \dfrac{1}{ {( n_{2})}^{2} } \bigg \}$

$\implies \overline{ \gamma } = R \bigg \{\dfrac{1}{ {(3) }^{2} } - \dfrac{1}{ {( \infty)}^{2} } \bigg \}$

$\implies \overline{ \gamma } = R \bigg \{\dfrac{1}{9 } - 0 \bigg \}$

$\implies \overline{ \gamma } = \dfrac{R}{9}$

So, required ratio will be:

$\implies \overline{ \gamma_{p} } : \overline{ \gamma_{l} }= 1 : 9$

Hope It Helps.