Question

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:-(a) 1(b) 4(c) 0.5(d) 2

Answer 1

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Answer 2

Answer:

Explanation:

For the last line of Balmer series  

n1 = 2, and n2 = ∞

= 1/ƛB=RZ²[1/n1²-1/n2²]

Substituting n1 and n2 in above equation we will get,

ƛB = 4/R

For the last line of Lymen series  

n1=1, and n2= ∞

1/ƛL=RZ²[1/n1²-1/n2²]

Substituting n1 and n2 in above equation we get,

ƛL = 1/R

Therefore ƛ = ƛB/ƛL

=4/R/1/R

=4

ƛ = 4:1

Thus, the ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is 4:1