Question

The ratio of weight of a man in a stationary lift and when it is moving downward with uniform acceleration 'a' is 3:2 . The value of a is

Answer 1

mg/m(g-a)= 3/2
a=g/3
So value of a is 1/3rd of accn due to gravity

Answer 2

Answer:

a=g/3

Explanation:

N=mg(stationary lift)

N= m(g-a) ( lift accelerating downwards)

N/N = mg/m(g-a)

3/2 = mg/ m(g-a)

therefore, a= g/3

mark this answer as BRAINLIEST.!!!!!!!!