Question

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is

Answer 1

Answer ➡️ 2/5

Explanation ↙️↙️↙️↙️

dU = .dT = n.(3R/2).dT

dQ = dQp = dH = nCp.dT = n.(5R/2).dT

dQ + dW = dU (as per sign convention in chemistry)

dW = dU - dQ = (-) n.R.dT

| dW/dQ | = (2/5)

Hope this helps you ☺️☺️