Math, asked by Nilay123, 1 year ago

The rationalising factor for 16^1/3 + 4^1/3 + 1 is
Please answer with explanation
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Answers

Answered by rohitkumargupta
19
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Answered by pinquancaro
7

Answer:

The solution of the given expression is 3.

Step-by-step explanation:

Given : Expression 16^{\frac{1}{3}}+4^{\frac{1}{3}}+ 1

To find : The rationalizing factor of the given expression?

Solution :

Expression 16^{\frac{1}{3}}+4^{\frac{1}{3}}+ 1

To solve the given expression multiply it by 4^{\frac{1}{3}}-1

=(4^{\frac{1}{3}}-1)16^{\frac{1}{3}}+4^{\frac{1}{3}}+ 1

=(4^{\frac{1}{3}})(16^{\frac{1}{3}}+4^{\frac{1}{3}}+ 1)-1(16^{\frac{1}{3}}+4^{\frac{1}{3}})

=4^{\frac{1}{3}}\times 4^2^{\frac{1}{3}}+4^{\frac{1}{3}}\times4^{\frac{1}{3}}+4^{\frac{1}{3}}\times 1-16^{\frac{1}{3}}-4^{\frac{1}{3}}+1)(-1)

=4^{\frac{1}{3}+\frac{2}{3}}+4^{\frac{2}{3}}+4^{\frac{1}{3}}-4^{\frac{2}{3}}-4^{\frac{1}{3}}-1

=4^{1}-1

=4-1

=3

Therefore, The solution of the given expression is 3.

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