The rationalising factor of √(2+√3) is
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underroot 2 + underroot 3 is the rationalising factor
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√(2+√3) x √(2+√3) = (2+√3)
Now, (2+√3) x (2-√3) = (2)2 - (√3)2 = 4 - 3 = 1
Overall rationalizing factor=
√(2+√3)(2-√3)
Now, (2+√3) x (2-√3) = (2)2 - (√3)2 = 4 - 3 = 1
Overall rationalizing factor=
√(2+√3)(2-√3)
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