Question

The rationalising factor of (3root3 + 5) options also there​

Answer 1

Answer:

$(a) = ( \sqrt{27} - 5)$

$= (3 - 5)$

$= ( - 2)$

$(b) = 5 \sqrt{3} - 5$

$= \sqrt{3}$

$(c) = \frac{1}{3 \sqrt{3} - 5 }$

$= \frac{1}{ - 2 \sqrt{3} }$

$= \frac{1 \times 2 \sqrt{3} }{ - 2 \sqrt{3} \times 2 \sqrt{3} }$

$= \frac{2 \sqrt{3} }{( - 2 \sqrt{3} ) {}^{2} }$

$= \frac{2 \sqrt{3} }{ - 2 \sqrt{3} \times 2 \sqrt{3} }$

$= - 2 \sqrt{3}$