Question

the rationalising factor of 7-2√3

Answer 1

7+2√3 is the rationalising factor

Answer 2

Rationalization factor of $\bf 7 - 2 \sqrt{3}$ is $\bf \red{7 + 2 \sqrt{3}}$.

Given:

• $7 - 2 \sqrt{3}$

To find:

• Find rationalization factor.

Solution:

Concept to be used:

• Rationalization factor is used to remove radical sign from the number.
• If a+√b is number then it's rationalization factor is a-√b.
• By doing this, Identity $(x + y)(x - y) = {x}^{2} - {y}^{2}$ can be used and number will be free from radical sign.

Step 1:

Write the rationalization factor.

As,

Given number is $7 - 2 \sqrt{3}$

so,

it's rationalization factor is $\bf 7 + 2 \sqrt{3}$

Step 2:

Reason of rationalization.

When RF is multiplied with the number.

$= (7 - 2 \sqrt{3} )(7 + 2 \sqrt{3} )$

or

Apply Identity.

$= ( {7}^{2} ) - ( {2 \sqrt{3} })^{2}$

or

$= 49 - 12$

or

$= 37$

By this way, radical sign is removed.

Thus,

Rationalization factor of $\bf 7 - 2 \sqrt{3}$ is $\bf 7 + 2 \sqrt{3}$.

Learn more:

1) rationalize the denominator of 1/ √3-√2

https://brainly.in/question/3713155

2) rationalize the denominator of

1/7+3√3

https://brainly.in/question/17305538