The rationalising factor of ∛9+1/∛9+1
Answers
Answered by
0
Answer:
cube root of 3 +1
Step-by-step explanation:
We know that :
(X^2 –X +1)(X+1) = X^3 +1
Substituting, X = cu root ( 3); we obtain
(cu root ( 9) - cu root ( 3) +1)(cube root(3) +1)
= ((cu root ( 3))^2 - cu root ( 3) +1)(cube root(3) +1)
= 3-1
=4
Accordingly,
(cu root of 9 -cu root of 3 +1)
= 4/ (cube root(3)+1)
Hence, the rationalizing factor is (cube root(3)+1)
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Answered by
0
Answer:
cube root of 3 +1
Step-by-step explanation:
We know that:
(X^2-X +1)(X+1) = X^3 +1
Substituting, X = cu root (3); we obtain
(cu root (9) cu root (3) +1)(cube root(3)
+1)
= ((cu root (3))^2 - cu root (3) +1)(cube
root(3) +1)
=3-1
=4
Accordingly,
(cu root of 9-cu root of 3 +1)
= 4/ (cube root(3)+1)
Hence, the rationalizing factor is (cube root(3)+1)
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