Math, asked by stayxarmy20, 3 days ago

The rationalising factor of ∛9+1/∛9+1​

Answers

Answered by pronelrinkumar30v
0

Answer:

cube root of 3 +1

Step-by-step explanation:

We know that :

(X^2 –X +1)(X+1) = X^3 +1

Substituting, X = cu root ( 3); we obtain

(cu root ( 9) - cu root ( 3) +1)(cube root(3) +1)

= ((cu root ( 3))^2 - cu root ( 3) +1)(cube root(3) +1)

= 3-1

=4

Accordingly,

(cu root of 9 -cu root of 3 +1)

= 4/ (cube root(3)+1)

Hence, the rationalizing factor is (cube root(3)+1)

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Answered by hemlatasantosh8584
0

Answer:

cube root of 3 +1

Step-by-step explanation:

We know that:

(X^2-X +1)(X+1) = X^3 +1

Substituting, X = cu root (3); we obtain

(cu root (9) cu root (3) +1)(cube root(3)

+1)

= ((cu root (3))^2 - cu root (3) +1)(cube

root(3) +1)

=3-1

=4

Accordingly,

(cu root of 9-cu root of 3 +1)

= 4/ (cube root(3)+1)

Hence, the rationalizing factor is (cube root(3)+1)

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