Question

the rationalizing factor of (2 3root 5 is) please solve it is urgent . it is rationalizing factor not rationalizing denominator​

Answer 1

Answer:

Step-by-step explanation:

2 ∛5 is irrational number.

let x =2 ∛5

x= 2*(5) ^1/3

Multiplying both sides by (5)^2/3

x*(5)^2/3=(5)^2/3 * 2*(5)^1/3

=2*(5)^(1/3+2/3)

=2*(5)^(3/3)=2*5¹ = 10 ( Rational number)

So x*(5)^2/3=10

So x becomes rational after multiplying by

5(2/3)

=(5²)^1/3=∛25

Thus ∛25 is the rationalizing factor