Question

The rationalizing factor of√3-2√5 is​

Answer 1

Step-by-step explanation:

The rationalising factor of √3-2√5

$= ( \sqrt{3} - 2 \sqrt{5} )( \sqrt{3} + 2 \sqrt{5} )$

$= ( { \sqrt{3} )}^{2} - ( {2 \sqrt{5} )}^{2} \: \:( ( {a}^{2} - {b}^{2} ) = (a + b)(a - b))$

$= 3 - 4\times 5$

$= 3 - 20$

$= - 17$