Math, asked by vtekale2005, 8 months ago

The rationalizing factor of
is

 \sqrt[n]{a \div b}

Answers

Answered by TheHeart
7

Question :-

The rationalizing factor of

is  \sqrt[n]{a \div b}

Solution :-

 \sqrt[n] {a \div b}  =   \sqrt[n] { \frac{a}{b} }

Now rationalize the denominator by

 \sqrt[n] {b}

Hence,

 \sqrt[n] { \frac{a}{b} }  \times  \frac{ \sqrt[n] {b} }{ \sqrt[n] {b} } =  \frac{ \sqrt[n] {a}  \times  \sqrt[n] {b} }{b}   =  \frac{ \sqrt[n] {ab} }{b}

Hint:-

 (\sqrt{n} ) {}^{2}  = n \\  \\

Eg:-

  •  (\sqrt{7} ) {}^{2}  = 7

Related term :-

  • The factor of multiplication by which rationalization is done, is called as rationalizing factor.

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