the ratios of the distance travelled in successive intervals of time by a body falling freely
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Answer:
1:3:5
hope this helps you better
Step-by-step explanation:
Distance travelled by an object in a particular second.
s
t
=u+
2
1
g(2t−1)
For 1 s
s
1
=0+
2
1
g ...(i)
For 2 s
s
2
=o+
2
1
g(4−1)
=
2
1
g×3 ... (ii)
For 3 s
s
3
=0+
2
1
g(6−1)=
2
1
g×5 ....(iii)
The ratio of distance
s
1
:s
2
:s
3
=
2
1
g:
2
3
g:
2
5
g=1:3:5
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