Math, asked by nirbhaysnas, 6 hours ago

the ratios of the distance travelled in successive intervals of time by a body falling freely

Answers

Answered by chnaidu1969
0

Answer:

1:3:5

hope this helps you better

Step-by-step explanation:

Distance travelled by an object in a particular second.

s

t

=u+

2

1

g(2t−1)

For 1 s

s

1

=0+

2

1

g ...(i)

For 2 s

s

2

=o+

2

1

g(4−1)

=

2

1

g×3 ... (ii)

For 3 s

s

3

=0+

2

1

g(6−1)=

2

1

g×5 ....(iii)

The ratio of distance

s

1

:s

2

:s

3

=

2

1

g:

2

3

g:

2

5

g=1:3:5

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