The RAW(Resident Welfare Association) of a colony has three different subcommittee with total of 12 members. First subcommittee is adult education committee, which looks after the literacy needs of the adults, the second subcommittee is health and cleanliness Committee, which looks after the health and cleanliness needs of the colony and third subcommittee is safety Committee, which looks after the safety needs of the colony. The number of members of the first subcommittee is half the sum of the members of the other two subcommittee and the number of members of the second subcommittee is the sum of the members of the other two subcommittee. Reduce the information in the form of algebraic statement and solve using matrix.
Answers
Each committee has 4 members
Step-by-step explanation:
three different subcommittee with total of 12 members.
Let say 1st has A members
2nd has B Members
3rd has 12- (A + B) Members
The number of members of the first subcommittee is half the sum of the members of the other two subcommittee
A = (B + 12 - (A + B))/2
=>2A = 12 - A
=> 3A = 12
=> A = 4
1st Committe has 4 members
number of members of the second subcommittee is the sum of the members of the other two subcommittee.
B = (A + 12 - (A + B) /2
=> 2B = 12 - B
=> 3B = 12
=> B = 4
2nd Committee has 4 members
3rd Committee has 12 - (4 +4) = 4 members
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