Physics, asked by kush8894, 1 year ago

The ray of light enters a rectangular glass slab of reafractive index 3 at an angle of incidence 60. It travels a distance 5cm inside the slab and emerges out of the slab. The perpendicular distance between the incident ray and emergent ray is

Answers

Answered by chinmaypandey8

3

D=sin(i-r)/cosr.use this formula to find the distance

Answered by surabhi48

2

Answer:

the distance between the incident and the emergent ray is 5√3/2

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