Question

The ray of light is incident at an angle 60°on one face of a rectangular slab of thickness 0.1m and refractive index 1.5. calculate the lateral shift produced

Answer 1

Give here:

i =60

t = 0.1m  

n = 1.5

now,

Lateral shift = d = t ×{sin (i-r)/ cos r}

n = sin i / sin r

sin r = sin 60   / 1.5

sin r = 0.5773

r = sin 0.5773 = 35.26

d = 0.1 ×{ sin (60-35.26) / cos 35.2} = 0.051 m

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Answer 2

Answer:

d= 0.051

Explanation:

lateral shift = d= t*[sin (i-r) /cos r ]

n=sin i /sin r

sin r = sin 60/1.5

sin r = 0.5773

r= sin 0.5773= 35.26

d=0.1[sin(60-35.26)/cos 35.2

d= 0.051

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