Question

the ray PQ incident narmally on the refrecting surface BA is refrected in in prism BAC made of material of refrective index 1.5 Calculate the path of ray through the prism . From which face will the ray emerge ? justify your answer.

Answer 1

i hope it hepls u.....

Answer 2

(The diagram missing in the question is attached below)

Given :

Refractive index  of the prism = 1.5

To Find :

The face from which the incident ray emerges

Solution :

• The incident angle of the ray is 90°, so the incident ray will not deviate while crossing the face AB of the prism

• The ray after passing through the face AB will fall on the face AC making an incidence angle 30°

• Refraction occurs at the face AC from denser to rarer medium, so by using snell’s law

          $\mu = \frac{Sini}{Sinr}$

          $Sinr=\mu \times Sini$

          $Sinr=1.5\times Sin30$

          $Sinr=0.75$

          $r=48.6 ^{0}$

The refracted angle is less than 90° so ray passes through the face AC