Question

The reactance of a capacitance at 50 Hz is 5 ohm. If the frequency is increased to 100 Hz, the new reactance is​

Answer 1

Explanation:

Capacitive reactance

Xc = 1/2πf

Therefore XC1/XC2 = 2πf2/2πf1

= 20/XC2 =100/50

= XC2 = 10

the new reactance is 10 OHMS

Answer 2

2.5ohm

Explanation :

Reactance : The measure of opposition to current flow offeredd by a material is known as reactance, denoted by R. The resistance offered to ac currents only bby inductors and capacitors is the reactance, denoted by X.

For capacitor,$XC = 1 / 2πf$

As given, XC1 = 5ohm

frequency f1 = 50Hz

XC2 = ?

frequency f2 = 100Hz

Applying the formula,

$XC1 / XC2 = 2πf2 / 2πf1$

$5 / XC2 = 100 / 50$

$5 / XC2 = 2$

  $XC2 = 5 / 2$

$XC2 = 2.5 ohm$

From the formula we can predict that as the frequency increases the reactance decreases as they are inversely proportional to each other.