Question

the reactance of the capacitance at 50 hertz is 5 ohms if the frequency is increased to 100 the then you reactance is​

Answer 1

Answer:

The new reactance is 2.5 ohm

Explanation:

We know that

Reactance of a capacitor is

Xc=1/2πfC

Given that Xc1=5Ω at 50 Hz

then Xc2 at 100 Hz will be

$\frac{Xc1}{Xc2} =\frac{\frac{1}{2\pi f_{1}C } }{\frac{1}{2\pi f_{2}C} } \\\frac{Xc1}{Xc2}=\frac{f_{2}}{f_{1}} \\ =\frac{5}{Xc2}= \frac{100}{50} \\Xc2= 250/100\\Xc2= 2.5 ohm$

The new reactance is 2.5 ohm

Then on simplifying we get

XC1XC2=f2f1

XC2=202

Therefore the new reactance of the capacitor is

XC2=10Ω

Read more on Brainly.in - https://brainly.in/question/11638315#readmore