Question

The reaction 2O3 —— >3O2, proceeds as follows
O3——> O2 +O (Fast)
O+O3——->2O2, (Slow)
The rate law expression for the reaction would be
(1) r = k[0312
(2) r = k[O312 [0211
(3) r = k[O31 [02]
(4) r = [0,11

Answer 1

Answer:

Option (4) is the correct one.

Answer 2

Hiii....

The reaction 2O3 —— >3O2, proceeds as follows

O3——> O2 +O (Fast)

O+O3——->2O2, (Slow)

The rate law expression for the reaction would be

• r = k[0312
• r = k[O312 [0211
• r = k[O31 [02]
• r = [0,11 ✔✔✔

@LittleButterfly ~♡~