The reaction 4 bromobenzyl chloride with NaCN in ethanol leads to
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This is the compound. Now the Cl is attached to a primary C so it will undergo SN2 reaction where the attacking nucleophile is the methoxide ion.
The final compound is
methoxy-(2-bromophenyl)methane
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Hi there,
Answer: 4 Bromobenzyl cyanide.
Explanation
4 bromobenzyl chloride will react with sodium cyanide in the presence of Ethanol to give 4 Bromobenzyl cyanide as a resulting compound. Sodium cyanide is an ionic compound. In this reaction, Cyanide act as a nucleophile and it will attack the carbon atom to replace Cl which gives 4 Bromobenzyl cyanide as a product.
Thanks for reading.
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